Show pageOld revisionsBacklinksFold/unfold allBack to top This page is read only. You can view the source, but not change it. Ask your administrator if you think this is wrong. ====== Thermal Conductivity ====== To make an hypothesis of how the thermal conductivity in our insulated box will evolve, we're basing in Fourier's Law and the heat convection-diffusion equation. $\vec{q}=-\kappa \nabla T$ $$$$ $\frac{\partial Q}{\partial t}=-\kappa \oint \limits_S\nabla T \vec{dA}$ $_{General Fourier's law}$ Where for the first form, $\vec{q}$ is the local heat flux density, $\kappa$ is the material's conductivity, $\nabla T$ is the gradient of the temperature. And for the second form $\frac{\partial Q}{\partial t}$ is the amount of heat transferred per unit time, and $\vec{dA}$ is an oriented surface area element. $\frac{\Delta Q}{\Delta t} = -\kappa A \frac{\Delta T}{\Delta x}$ $$$$ $_{Fourier's law applied to an homogeneous material of 1D geometry between two endpoints at constant temperature}$ Where $\Delta T$ is the difference of temperature between the edges, and $\Delta x$ is the distance between them. $\frac{\partial T}{\partial t}=\nabla.(\frac{\kappa}{\rho c_{\rho}} \nabla T) - \nabla. (\frac{\partial T}{\partial x}) + R$ $$$$ $_{heat convection-difussion equation}$ Where $\frac{\partial T}{\partial t}$ is the temperature transfer per unit time, $\rho$ is the density, $c_{\rho}$ is specific heat capacity, $\frac{\partial T}{\partial x}$ is the speed of the temperature transfer in the outside direction, and $R$ is the source of heat. $\nabla$ stands for the gradient and $\nabla.$ the divergence operators. {{ :thermal_diffusion.png?nolink |}} ====== Experiment ====== Objective: We want to know the behavior of the rock wool and polyurethane foam used as insulation materials during a long period of time. Materials: Sensirion SHT21 Cardboard box (20x20x14 cm) Rock wool (density 50kg/m3, Thermal conductivity (R) =0.039, specific heat 1500 J/Kg°C) {{ :rock_wool.jpg?nolink&300 |}} Polyurethane Foam (density 150kg/m3, Thermal conductivity (R) =0.04, specific heat 1500 J/Kg°C) {{ :polyurethane_foam.jpg?nolink&300 |}} Procedure: We cover the interior of the cardboard boxes with a 40mm homogeneous layer of the insulation material, the sensor inside will recovered the data (temperature, humidity, and time) Results: {{:rock_temp.png?nolink&300 |}} orb/thermal_insulation.txt Last modified: 6 years agoby sam